13 Modeling With Linear Functions Answer Key

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13 modeling with linear functions answer key is a crucial resource for students learning about the applications of linear equations in real-world scenarios. This article will delve into the concept of modeling with linear functions, outline the types of problems typically encountered, and provide a comprehensive answer key to assist learners in mastering this essential algebraic skill. By understanding how to model various situations using linear functions, students can better prepare themselves for more advanced mathematical concepts and their applications in fields such as economics, engineering, and the social sciences.

Understanding Linear Functions



Definition of Linear Functions



Linear functions are mathematical expressions that represent a straight line when graphed on a coordinate plane. The general form of a linear function is:

\[ y = mx + b \]

where:
- \( m \) is the slope of the line,
- \( b \) is the y-intercept (the point where the line crosses the y-axis),
- \( x \) is the independent variable, and
- \( y \) is the dependent variable.

Characteristics of Linear Functions



When dealing with linear functions, it's essential to understand their characteristics:

1. Slope (m): Indicates the rate of change of \( y \) with respect to \( x \). A positive slope means that as \( x \) increases, \( y \) also increases, while a negative slope indicates the opposite.

2. Y-intercept (b): This is the value of \( y \) when \( x = 0 \). It provides a starting point for the graph of the function.

3. Graphical Representation: The graph of a linear function is a straight line, which can be determined by plotting at least two points derived from the equation.

4. Domain and Range: For linear functions, both the domain (the set of all possible \( x \) values) and the range (the set of all possible \( y \) values) are typically all real numbers.

Modeling Real-World Situations with Linear Functions



Linear functions are often used to model real-world situations, allowing us to make predictions or understand relationships between variables. Here are some common applications:

Examples of Situations



1. Cost Analysis: A company might want to model the relationship between the number of products sold and total revenue.
2. Distance and Time: The relationship between distance traveled and time taken at a constant speed can be represented as a linear function.
3. Temperature Changes: The change in temperature over time can also be modeled linearly, particularly in controlled environments.
4. Population Growth: In some cases, populations may grow at a constant rate, which can be modeled using linear functions.

Common Problems in Modeling with Linear Functions



When learning to model with linear functions, students often encounter a variety of problem types. Here are some common examples:

Problem Types



1. Finding the Equation: Given two points, students may be asked to find the linear equation that passes through them.
2. Interpreting the Slope and Y-intercept: Students might need to explain what the slope and y-intercept represent in a given context.
3. Graphing Linear Functions: Students may be tasked with graphing a linear function based on its equation.
4. Solving Real-World Problems: This involves creating a linear model from a word problem and using it to calculate specific values.

13 Modeling with Linear Functions Answer Key



Below is the answer key for a set of 13 problems designed to help students practice modeling with linear functions. Each problem will be outlined, followed by a detailed solution.

Problem 1: Finding the Equation



Problem: Find the equation of the line that passes through the points (2, 3) and (4, 7).

Solution:
1. Calculate the slope \( m \):
\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{7 - 3}{4 - 2} = \frac{4}{2} = 2 \]

2. Use point-slope form:
\[ y - y_1 = m(x - x_1) \]
Using point (2, 3):
\[ y - 3 = 2(x - 2) \]
\[ y = 2x - 4 + 3 \]
\[ y = 2x - 1 \]

Answer: \( y = 2x - 1 \)

Problem 2: Interpreting Slope and Y-Intercept



Problem: Given the equation \( y = 4x + 5 \), identify the slope and the y-intercept.

Solution:
- Slope \( m = 4 \) (indicates the output increases by 4 for every 1 unit increase in \( x \)).
- Y-intercept \( b = 5 \) (the line crosses the y-axis at (0, 5)).

Answer: Slope = 4, Y-Intercept = 5

Problem 3: Graphing Linear Functions



Problem: Graph the function \( y = -3x + 2 \).

Solution:
1. Identify the y-intercept (2).
2. Use the slope (-3) to find another point. From (0, 2), move down 3 units and right 1 unit to (1, -1).
3. Plot points (0, 2) and (1, -1) and draw the line through these points.

Answer: The graph of \( y = -3x + 2 \) is a line with a y-intercept at (0, 2) and slope -3.

Problem 4: Solving Real-World Problems



Problem: A taxi charges a flat fee of $3 plus $2 for each mile driven. Write the linear function representing the total cost \( C \) in terms of miles \( m \).

Solution:
Using the equation \( C = 2m + 3 \):
- Slope = 2 (cost per mile),
- Y-intercept = 3 (base fare).

Answer: \( C = 2m + 3 \)

Problem 5: Finding the Y-Intercept



Problem: If the equation of a line is \( y = 6x - 12 \), what is the y-intercept?

Solution:
The y-intercept can be found by setting \( x = 0 \):
\[ y = 6(0) - 12 = -12 \]

Answer: Y-intercept = -12

Problem 6: Parallel Lines



Problem: Write the equation of a line parallel to \( y = 2x + 1 \) and passing through the point (3, 4).

Solution:
1. The slope of the parallel line is also 2.
2. Using point-slope form:
\[ y - 4 = 2(x - 3) \]
\[ y = 2x - 6 + 4 \]
\[ y = 2x - 2 \]

Answer: \( y = 2x - 2 \)

Problem 7: Perpendicular Lines



Problem: Find the equation of a line perpendicular to \( y = 1/2x - 3 \) that passes through the point (2, 1).

Solution:
1. The slope of the given line is \( \frac{1}{2} \), so the slope of the perpendicular line is \( -2 \).
2. Using point-slope form:
\[ y - 1 = -2(x - 2) \]
\[ y = -2x + 4 + 1 \]
\[ y = -2x + 5 \]

Answer: \( y = -2x + 5 \)

Problem 8: Revenue Model



Problem: A company sells widgets for $20 each, with a fixed cost of $100. Write a linear function for the total revenue \( R \) based on the number of widgets \( n \).

Solution:
Using the equation:
\[ R = 20n \] (ignoring fixed costs for revenue calculation).

Answer: \( R = 20n \)

Problem 9: Temperature Change



Problem: The temperature rises at a rate of 3 degrees per hour starting from 15 degrees. Write the linear function for temperature \( T \) in terms of hours \( h \).

Solution:
The equation will be:
\[ T = 3h + 15 \]

Answer: \( T = 3h + 15 \)

Problem 10: Distance and Time



Problem: A car travels at a constant speed of 60 miles per hour. Write the distance \( d \) in terms of time \( t \).

Solution:
Using the formula:
\[ d = 60t \]

Answer: \( d = 60t \)

Problem 11: Cost Function



Problem:

Frequently Asked Questions


What is the primary purpose of using linear functions in modeling?

The primary purpose of using linear functions in modeling is to represent relationships between variables in a way that allows for predictions and analysis of trends.

How can you determine if a set of data points can be modeled by a linear function?

You can determine if a set of data points can be modeled by a linear function by plotting the points on a graph and checking if they form a straight line or by calculating the correlation coefficient.

What is the standard form of a linear equation and what do the variables represent?

The standard form of a linear equation is Ax + By = C, where A, B, and C are constants, and x and y are the variables representing the coordinates of points on the line.

What is the significance of the slope in a linear function?

The slope of a linear function indicates the rate of change of the dependent variable with respect to the independent variable, representing how steep the line is.

How do you find the y-intercept of a linear function from its equation?

You find the y-intercept of a linear function from its equation by setting the value of x to zero and solving for y.

What role does the x-intercept play in a linear function?

The x-intercept is the point where the line crosses the x-axis, indicating the value of x when y equals zero, which is useful for understanding the function's behavior.

Can linear functions be used for non-linear data? If so, how?

Linear functions can be used to approximate non-linear data within a limited range by using techniques such as linear regression, but they may not accurately represent the overall trend.