Bohr Model Practice Problems

Advertisement

Bohr model practice problems are essential for students and enthusiasts of atomic physics to understand the quantized nature of electron energy levels. Developed by Niels Bohr in 1913, the Bohr model provides a simplified yet powerful way to visualize the arrangement and behavior of electrons in hydrogen-like atoms. Through practice problems, learners can grasp key concepts such as energy levels, electron transitions, and spectral lines. This article will delve into various practice problems, offering a step-by-step approach to solving them while reinforcing the fundamental principles of the Bohr model.

Understanding the Bohr Model



The Bohr model describes the atom as a small, positively charged nucleus surrounded by electrons that travel in circular orbits. Key features of the model include:

- Quantized Orbits: Electrons can only occupy certain allowed orbits with fixed radii and energies.
- Energy Levels: The energy of an electron is determined by its distance from the nucleus.
- Electron Transitions: When an electron moves between orbits, it absorbs or emits a photon, resulting in spectral lines.

The fundamental equation governing the energy levels in the Bohr model is:

\[
E_n = -\frac{13.6 \, \text{eV}}{n^2}
\]

Where \( E_n \) is the energy of the electron in the nth orbit, and \( n \) is the principal quantum number (1, 2, 3,...).

Practice Problems



To solidify your understanding of the Bohr model, we will explore several practice problems that cover different aspects of the model.

Problem 1: Calculating Energy Levels



Question: Calculate the energy of the electron in the first three energy levels of a hydrogen atom.

Solution:

Using the formula \( E_n = -\frac{13.6 \, \text{eV}}{n^2} \):

1. For \( n = 1 \):
\[
E_1 = -\frac{13.6 \, \text{eV}}{1^2} = -13.6 \, \text{eV}
\]

2. For \( n = 2 \):
\[
E_2 = -\frac{13.6 \, \text{eV}}{2^2} = -3.4 \, \text{eV}
\]

3. For \( n = 3 \):
\[
E_3 = -\frac{13.6 \, \text{eV}}{3^2} = -1.51 \, \text{eV}
\]

Thus, the energies of the first three levels are -13.6 eV, -3.4 eV, and -1.51 eV, respectively.

Problem 2: Electron Transition and Photon Emission



Question: An electron in a hydrogen atom transitions from the \( n = 3 \) level to the \( n = 2 \) level. Calculate the energy of the photon emitted during this transition.

Solution:

1. First, calculate the energies of the levels:
- \( E_3 = -1.51 \, \text{eV} \)
- \( E_2 = -3.4 \, \text{eV} \)

2. The energy of the photon emitted (\( E_{photon} \)) is given by the difference in energy levels:
\[
E_{photon} = E_2 - E_3 = (-3.4) - (-1.51) = -3.4 + 1.51 = -1.89 \, \text{eV}
\]

Thus, the energy of the emitted photon is 1.89 eV.

Problem 3: Wavelength Calculation



Question: Using the energy calculated in Problem 2, find the wavelength of the emitted photon.

Solution:

The energy of a photon is related to its wavelength (\( \lambda \)) by the equation:

\[
E = \frac{hc}{\lambda}
\]

Where:
- \( h = 6.626 \times 10^{-34} \, \text{J s} \) (Planck's constant)
- \( c = 3 \times 10^8 \, \text{m/s} \) (speed of light)
- Convert energy from eV to Joules: \( 1 \, \text{eV} = 1.602 \times 10^{-19} \, \text{J} \)

1. Convert 1.89 eV to Joules:
\[
E = 1.89 \, \text{eV} \times 1.602 \times 10^{-19} \, \text{J/eV} = 3.02 \times 10^{-19} \, \text{J}
\]

2. Rearranging the equation for wavelength:
\[
\lambda = \frac{hc}{E}
\]

3. Now substitute the values:
\[
\lambda = \frac{(6.626 \times 10^{-34} \, \text{J s})(3 \times 10^8 \, \text{m/s})}{3.02 \times 10^{-19} \, \text{J}} \approx 6.60 \times 10^{-7} \, \text{m} = 660 \, \text{nm}
\]

Thus, the wavelength of the emitted photon is approximately 660 nm.

Problem 4: Finding the Radius of Electron Orbits



Question: Determine the radius of the electron's orbit in the hydrogen atom for the \( n = 2 \) energy level.

Solution:

The radius of the nth orbit is given by the formula:

\[
r_n = n^2 \times a_0
\]

Where \( a_0 = 5.29 \times 10^{-11} \, \text{m} \) (Bohr radius).

1. For \( n = 2 \):
\[
r_2 = 2^2 \times 5.29 \times 10^{-11} \, \text{m} = 4 \times 5.29 \times 10^{-11} \, \text{m} = 2.116 \times 10^{-10} \, \text{m}
\]

Thus, the radius of the electron's orbit for the \( n = 2 \) level is approximately \( 2.116 \times 10^{-10} \, \text{m} \).

Conclusion



The Bohr model provides valuable insights into the behavior of electrons in atoms, particularly hydrogen. By working through various practice problems, students can solidify their understanding of energy levels, electron transitions, and the resulting spectral emissions. The model, while not comprehensive for all elements, serves as an excellent introduction to quantum mechanics and atomic structure. Continued practice with problems like those presented in this article will enhance comprehension of the quantized nature of matter and the fascinating world of atomic physics.

Frequently Asked Questions


What is the Bohr model and how does it explain the structure of an atom?

The Bohr model is a planetary model of the atom proposed by Niels Bohr in 1913. It describes the atom as having a small, positively charged nucleus surrounded by electrons that orbit in defined paths or energy levels. The model explains the quantization of electron orbits and the emission or absorption of light as electrons move between these energy levels.

How do you calculate the energy levels of an electron in a hydrogen atom using the Bohr model?

The energy levels of an electron in a hydrogen atom can be calculated using the formula: E_n = -13.6 eV / n², where E_n is the energy of the electron at level n, and n is the principal quantum number (n = 1, 2, 3, ...).

What is the significance of the principal quantum number in the Bohr model?

The principal quantum number (n) indicates the energy level of an electron in the Bohr model. It determines the size and energy of the electron's orbit, with higher values of n corresponding to larger orbits and higher energy levels.

How can you determine the wavelength of light emitted during an electron transition in the Bohr model?

The wavelength of emitted light during an electron transition can be calculated using the Rydberg formula: 1/λ = R_H (1/n₁² - 1/n₂²), where λ is the wavelength, R_H is the Rydberg constant (approximately 1.097 x 10^7 m⁻¹), and n₁ and n₂ are the principal quantum numbers of the lower and higher energy states, respectively.

What is the formula for the radius of an electron's orbit in a hydrogen atom according to the Bohr model?

The radius of an electron's orbit in a hydrogen atom can be calculated using the formula: r_n = n² a₀, where r_n is the radius of the nth orbit and a₀ (the Bohr radius) is approximately 0.529 Å (angstroms).

How does the Bohr model explain the emission spectrum of hydrogen?

The Bohr model explains the emission spectrum of hydrogen by proposing that when an electron transitions from a higher energy level to a lower one, it emits a photon of light with energy equal to the difference between the two levels. This results in specific wavelengths of light, leading to the characteristic spectral lines of hydrogen.

What limitations does the Bohr model have in explaining atomic structure?

The Bohr model has limitations, including its inability to accurately predict the spectra of multi-electron atoms, its neglect of electron-electron interactions, and its reliance on circular orbits. It also does not incorporate the principles of quantum mechanics that describe electron behavior more accurately.

In a practice problem, how would you approach finding the energy of an electron in the third energy level of a hydrogen atom?

To find the energy of an electron in the third energy level (n=3) of a hydrogen atom, use the formula E_n = -13.6 eV / n². Plugging in n=3 gives E_3 = -13.6 eV / 3² = -13.6 eV / 9 = -1.51 eV.