Electron Affinity Practice Problems

Advertisement

Electron affinity practice problems are essential for students and chemistry enthusiasts who want to deepen their understanding of this fundamental concept in atomic chemistry. Electron affinity refers to the energy change that occurs when an electron is added to a neutral atom to form an anion. This property can vary significantly among different elements and plays a critical role in predicting the behavior of atoms during chemical reactions. This article will explore electron affinity, its significance, and how to solve practice problems effectively.

Understanding Electron Affinity



Electron affinity is defined as the amount of energy released when an electron is added to a neutral atom. The process can be represented as follows:

\[
\text{X} + e^- \rightarrow \text{X}^- + \Delta E
\]

Where:
- \( \text{X} \) is the neutral atom.
- \( e^- \) is the added electron.
- \( \text{X}^- \) is the resulting anion.
- \( \Delta E \) is the energy change associated with the process, typically measured in electron volts (eV) or kilojoules per mole (kJ/mol).

Significance of Electron Affinity



1. Predicting Reactivity: Electron affinity helps predict how easily an atom can gain an electron. Atoms with high electron affinity are more likely to form anions, influencing their reactivity in chemical reactions.

2. Formation of Ionic Compounds: Understanding the electron affinity of elements is crucial when predicting the formation of ionic compounds. Atoms with high electron affinities can attract electrons from atoms with low ionization energies.

3. Periodic Trends: Electron affinity varies across the periodic table. Generally, it increases across a period from left to right and decreases down a group. This trend is essential for predicting the chemical behavior of elements.

Practice Problems on Electron Affinity



To solidify your understanding of electron affinity, it’s helpful to work through practice problems. Below are several examples, along with their solutions:

Problem 1: Identifying Electron Affinity Trends



Question: Arrange the following elements in order of increasing electron affinity: Cl, F, Br, I.

Solution:
- The trend in electron affinity generally increases across a period and decreases down a group.
- For the halogens given:
- F has the highest electron affinity due to its small size and high electronegativity.
- Cl has a slightly lower electron affinity than F but is still high.
- Br and I have lower electron affinities than Cl and F, with I having the lowest due to its larger atomic size.

Order: I < Br < Cl < F

Problem 2: Energy Change Calculation



Question: What is the energy change when 1 mole of chlorine gas (\( \text{Cl}_2 \)) is converted to chloride ions (\( \text{2Cl}^- \))? Given that the electron affinity of Cl is -349 kJ/mol.

Solution:
- When 1 mole of \( \text{Cl}_2 \) gains electrons, it can be represented as:

\[
\text{Cl}_2 + 2e^- \rightarrow 2\text{Cl}^-
\]

- Since the electron affinity of Cl is -349 kJ/mol, for 1 mole of \( \text{Cl}_2 \):

\[
\Delta E = 2 \times (-349 \text{ kJ/mol}) = -698 \text{ kJ/mol}
\]

Thus, the energy change when converting 1 mole of \( \text{Cl}_2 \) to \( \text{2Cl}^- \) is -698 kJ/mol.

Problem 3: Comparing Electron Affinities



Question: Compare the electron affinities of oxygen and sulfur. Which element has a higher electron affinity and why?

Solution:
- Oxygen has a higher electron affinity than sulfur. This is primarily due to the smaller atomic radius of oxygen, which allows it to attract additional electrons more effectively than sulfur.
- The electron affinity of oxygen is about -141 kJ/mol, while that of sulfur is approximately -200 kJ/mol. However, in this case, the absolute value of sulfur's electron affinity is lower, indicating that it is less favorable for sulfur to gain an electron compared to oxygen.

Conclusion: Oxygen has a higher electron affinity than sulfur, largely due to its smaller atomic size and higher electronegativity.

Practice Problems for Self-Assessment



For further practice, here are some additional problems you can work on:



  1. Calculate the energy change when 1 mole of sodium (\( \text{Na} \)) gains an electron. The electron affinity of sodium is -0.5 eV.


  2. Arrange the following elements in order of decreasing electron affinity: N, P, As, Sb.


  3. Explain why noble gases generally have positive electron affinities, while halogens have negative values.


  4. Given the electron affinity values of Br (-324 kJ/mol) and I (-295 kJ/mol), which element will more readily form an anion and why?



Answers to Self-Assessment Problems



1. The energy change for sodium gaining an electron:
- \( \Delta E = -0.5 \text{ eV} \times 96.485 \text{ kJ/eV} = -48.6 \text{ kJ/mol} \).

2. The order of decreasing electron affinity: N > P > As > Sb.

3. Noble gases have positive electron affinities because they have a full valence shell and do not readily accept electrons, while halogens have negative values due to their strong tendency to gain an electron to achieve a stable electron configuration.

4. Bromine will more readily form an anion compared to iodine, as it has a more negative electron affinity value, indicating a greater tendency to gain an electron.

Conclusion



Electron affinity is a crucial concept in understanding atomic behavior and chemical reactivity. Through practice problems and self-assessment, students can refine their skills in predicting and calculating electron affinities. By grasping the trends and implications of electron affinity, learners can develop a stronger foundation in chemistry and enhance their problem-solving abilities. Whether you’re preparing for exams or simply exploring the fascinating world of chemistry, mastering electron affinity is an invaluable step in your educational journey.

Frequently Asked Questions


What is electron affinity and why is it important in chemistry?

Electron affinity is the amount of energy released when an electron is added to a neutral atom to form a negative ion. It is important because it helps predict how an atom will behave in chemical reactions, particularly in forming anions.

How do you calculate the electron affinity of an atom using experimental data?

To calculate the electron affinity, you can use the formula: EA = E(final state) - E(initial state), where E represents the energy of the system before and after the addition of an electron.

What is the trend of electron affinity in the periodic table?

Electron affinity generally increases across a period from left to right and decreases down a group. This is due to increasing nuclear charge and decreasing atomic radius affecting the attraction of added electrons.

Can you provide an example of a practice problem involving electron affinity?

Sure! If the electron affinity of chlorine is approximately -349 kJ/mol, how much energy is released when 2 moles of chlorine gain electrons? The answer is -698 kJ, since you multiply the energy released per mole by 2.

What factors influence the electron affinity of an element?

Factors include atomic size, effective nuclear charge, electron shielding, and electron-electron repulsion in the atom. Smaller atoms with higher nuclear charge tend to have higher electron affinities.

How does the electron affinity of noble gases compare to that of halogens?

Noble gases generally have positive or very low electron affinities because they already have a full valence shell, making them less likely to gain additional electrons. In contrast, halogens have high electron affinities as they seek to achieve a full outer shell.

What is a common misconception about electron affinity?

A common misconception is that all elements have negative electron affinities. In reality, some elements, particularly noble gases, can have a positive electron affinity, indicating that energy is required to add an electron.